All Courses
All Courses
Courses by Software
Courses by Semester
Courses by Domain
Tool-focused Courses
Machine learning
POPULAR COURSES
Success Stories
MIX DESIGN FOR M35 GRADE CONCRETE WITH FLY ASH 1. TARGET MEAN STRENGTH F'ck= fck +1.65x s s = 5 N/mm2 from table 1 IS 10262:2009, standard deviation, s fck = 35N/mm2 F'ck = 35 +1.65 x5 =43.5N/mm2 2. WATER CEMENT RATIO assume atmospheric condition…
Vejetha Sajeevan
updated on 25 May 2021
MIX DESIGN FOR M35 GRADE CONCRETE WITH FLY ASH
1. TARGET MEAN STRENGTH
F'ck= fck +1.65x s
s = 5 N/mm2 from table 1 IS 10262:2009, standard deviation, s
fck = 35N/mm2
F'ck = 35 +1.65 x5 =43.5N/mm2
2. WATER CEMENT RATIO
assume atmospheric condition = extreme
tabel 5 - IS456 2000
at extreme the w/c ratio=0.40
M35= w/c ratio =0.45
since 0.40 is lesser than 0.45, the w/c ratio with better workability is 0.40
3. MINIMUM CEMENT CONTENT
360kg/m3 for 0.40 w/c ratio
water content = nominal size of aggregates = 20mm
table IS10262 2009
minimum water content = 186kg
slump ranges from 25 to 50mm
As superplasticizers(20% reduced= 100-20= 80%)
186x80%= 148.8 ~ water content , W= 149L
4. CEMENT + FLYASH
w/c ratio =0.40
W = 149kg
Cement + flyash =149/0.40 =372.5~ 370kg/m3
minimum cement content = 360kg/m3
360<370 , hence okay
increase by 10% = 370x0.10 +370 = 407kg/m3
W = 149kg,
water cement ratio =149/407= 0.366
flyash at 30%, total cementitious material content
= 407x30/100 = 122Kg/m3
cement = 407-122= 285kg/m3
saving for cement using fly ash= 370 -285 = 85kg/m3
fly ash =122kg/m3
5. VOLUME OF FINE AND COARSE AGGREGATES(FA AND CA)
FA -> ZONE 1 TABLE 4, IS383
CA -> TABLE 2 IS 383
nominal size of aggregates= 20mm
Fine aggregates Zone 1, therefore
Volume of coarse aggregates = 0.60
water cement ratio = 0.4(+/-0.01 for every +/- 0.005)
so volume of CA =0.62
volume of FA = 1-0.62 =0.38
6. VOLUME OF CONCRETE =1m3
VOLUME OF CEMENT =285/3.15 X 1/1000 =0.090m3
VOLUME OF FLYASH =122/2.2 X 1/1000=0.055m3
VOLUME OF WATER =149/1 X 1/1000 =0.149m3
VOLUME OF ADMIXTURE =7.6/1.145 X 1/1000=0.006m3
VOLUME OF CA AND FA = a -(b+c+d+e)=1-(0.090+0.055+0.149+0.006)=0.7m3
MASS OF COARSE AGGREGATE =0.7X0.62X2.74X1000= 1189.16kg/m3
MASS OF FINE AGGREGATE =0.7X0.38X2.74X1000 =728 kg/m3
7. RESULTS
CEMENT =785kg/m3
FLYASH =122kg/m2
WATER =149 kg
COARSE AGGREGATE =1189 kg/m3
FINE AGGREGATE = 728 kg/m3
CHEMICAL ADMIXTURE = 7.6kg/m3
WATER CEMENT RATIO = 0.366
TRIAL MIX RATIO = 285 :728:1189 = 1:2.55:4.17 =C:FA:CA
trial mix ratio should match the workability , durability and minimum working strength of M35 grade concrete , if not further trials should be done.
CONCRETE MIX DESIGN FOR M50 WITHOUT FLYASH
F’ck = fck + 1.65 x S …………………….. S= standard deviation from the table 1 IS10262:2009 = 5
= 50 +1.65 X 5 =58.25 N/mm2
TABLE 5 IS456:2000
Extreme exposure condition ; W/C RATIO = 0.40
M50 ; W/C =0.40
Lower the ratio better the workability, there the w/c ratio = 0.40
MINIMUM CEMENT CONTENT
FOR M 50 -> 360 kg/m3
Nominal size of aggregates = 20mm
Minimum water content W= 186 L
Slump ranges from 25 – 50mm
As superplasticisers used , 20% reduced
100-20 =80%
186x80% =148.8 ~ water content = 149L
Water cement ratio = 0.4
W = 149L
CEMENT CONTENT =C = 149/0.40 =372.5 ~ 375 kg/m3
Minimum cemnt content = 360kg/m3
Since 360 <370, hence okay.
COARSE AGGREGATE = ZONE 1 TABLE 4 IS383
FINE AGGREGATE = TABLE 2 IS383
According to table 3 IS10262 :2009
Nominal Size of aggregates =20mm
Fine aggregates , Zone 1 ;
Volume of coarse aggregate =0.60
Water cement ratio = 0.40
(+/-0.01 for every +/-0.005)
Volume of coarse aggregate = 0.62
Volume of fine aggregate =1-0.62 =0.38
VOLUME OF CONCRETE =1m3
VOLUME OF CEMENT =375/3.15 X 1/1000 =0.118m3
VOLUME OF WATER =149/1 X 1/1000 =0.149m3
VOLUME OF ADMIXTURE =7.6/1.145 X 1/1000=0.006m3
VOLUME OF CA AND FA = a -(b+c+d+e)=1-(0.118+0.149+0.006)=0.727m3
MASS OF COARSE AGGREGATE =0.727X0.62X2.74X1000= 1235.02kg/m3
MASS OF FINE AGGREGATE =0.727X0.38X2.74X1000 =756.9 kg/m3
CEMENT =375 kg/m3
WATER =149 kg
COARSE AGGREGATE =1235 kg/m3
FINE AGGREGATE = 756.9kg/m3
CHEMICAL ADMIXTURE = 7.6kg/m3
WATER CEMENT RATIO = 0.40
TRIAL MIX RATIO = 375:757:1235= 1:2.01: 3.29=C:FA:CA
trial mix ratio should match the workability , durability and minimum working strength of M50 grade concrete , if not further trials should be done.
Leave a comment
Thanks for choosing to leave a comment. Please keep in mind that all the comments are moderated as per our comment policy, and your email will not be published for privacy reasons. Please leave a personal & meaningful conversation.
Other comments...
Project 1
### Given Data- Floor thickness: t=120 mm=0.12 m- Density of concrete: ρ=24 kN/m3- Floor finish and mechanical loads: 3 kPa- Live load: 5 kPa- Modulus of elasticity of concrete: E=10 GPa- Beam dimensions: \( 500 \text{ mm} \times…
03 Jun 2024 01:44 PM IST
Project 2
Aim - To Model & Design a Proposed PEB Warehouse using STAAD. Pro. Introduction - Here we model and design the PEB warehouse building. As per given description, material data, specification we can design it. PEB - Pre engineered buildings are factory built buildings shipped to site and assembled by bolting together. The…
14 May 2023 12:08 PM IST
Week 12 Challenge
Design of Foundation in STAAD Foundation 1. Isolated Footing Design isolated footing for a column 300 mm x 450 mm, carrying axial load of 1500 kN and Mu = 150 kNm using STAAD. Foundation. Assume that the moment is reversible. The safe bearing capacity of the soil is 200 kN/m2 at a depth of 1 metre from ground level. Use…
09 May 2023 07:59 AM IST
Week 11 Challenge
Analysis & Design of Pipe Rack Structure in STAAD.pro Question 1:- Friction load determination A pipe carrying LNG rests on the shoe having vertical force of 125 kN. Calculate the Friction load on the axis. Also find the friction force, if TEFLON pad is used between shoe and pipe support. Aim:- To calculate…
09 May 2023 06:47 AM IST
Related Courses
Skill-Lync offers industry relevant advanced engineering courses for engineering students by partnering with industry experts.
© 2025 Skill-Lync Inc. All Rights Reserved.